Integrand size = 24, antiderivative size = 291 \[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\frac {(e x)^{2 n}}{2 a e n}-\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}-\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d^2 e n}+\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d^2 e n} \]
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Time = 0.41 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {5549, 5545, 4276, 3403, 2296, 2221, 2317, 2438} \[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=-\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{d x^n+c}}{b-\sqrt {a^2+b^2}}\right )}{a d^2 e n \sqrt {a^2+b^2}}+\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{d x^n+c}}{b+\sqrt {a^2+b^2}}\right )}{a d^2 e n \sqrt {a^2+b^2}}-\frac {b x^{-n} (e x)^{2 n} \log \left (\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}+1\right )}{a d e n \sqrt {a^2+b^2}}+\frac {b x^{-n} (e x)^{2 n} \log \left (\frac {a e^{c+d x^n}}{\sqrt {a^2+b^2}+b}+1\right )}{a d e n \sqrt {a^2+b^2}}+\frac {(e x)^{2 n}}{2 a e n} \]
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Rule 2221
Rule 2296
Rule 2317
Rule 2438
Rule 3403
Rule 4276
Rule 5545
Rule 5549
Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{-2 n} (e x)^{2 n}\right ) \int \frac {x^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx}{e} \\ & = \frac {\left (x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {x}{a+b \text {csch}(c+d x)} \, dx,x,x^n\right )}{e n} \\ & = \frac {\left (x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \left (\frac {x}{a}-\frac {b x}{a (b+a \sinh (c+d x))}\right ) \, dx,x,x^n\right )}{e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {\left (b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {x}{b+a \sinh (c+d x)} \, dx,x,x^n\right )}{a e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {\left (2 b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {e^{c+d x} x}{-a+2 b e^{c+d x}+a e^{2 (c+d x)}} \, dx,x,x^n\right )}{a e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {\left (2 b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {e^{c+d x} x}{2 b-2 \sqrt {a^2+b^2}+2 a e^{c+d x}} \, dx,x,x^n\right )}{\sqrt {a^2+b^2} e n}+\frac {\left (2 b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {e^{c+d x} x}{2 b+2 \sqrt {a^2+b^2}+2 a e^{c+d x}} \, dx,x,x^n\right )}{\sqrt {a^2+b^2} e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {\left (b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \log \left (1+\frac {2 a e^{c+d x}}{2 b-2 \sqrt {a^2+b^2}}\right ) \, dx,x,x^n\right )}{a \sqrt {a^2+b^2} d e n}-\frac {\left (b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \log \left (1+\frac {2 a e^{c+d x}}{2 b+2 \sqrt {a^2+b^2}}\right ) \, dx,x,x^n\right )}{a \sqrt {a^2+b^2} d e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {\left (b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 a x}{2 b-2 \sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x^n}\right )}{a \sqrt {a^2+b^2} d^2 e n}-\frac {\left (b x^{-2 n} (e x)^{2 n}\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {2 a x}{2 b+2 \sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x^n}\right )}{a \sqrt {a^2+b^2} d^2 e n} \\ & = \frac {(e x)^{2 n}}{2 a e n}-\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}+\frac {b x^{-n} (e x)^{2 n} \log \left (1+\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d e n}-\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{c+d x^n}}{b-\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d^2 e n}+\frac {b x^{-2 n} (e x)^{2 n} \operatorname {PolyLog}\left (2,-\frac {a e^{c+d x^n}}{b+\sqrt {a^2+b^2}}\right )}{a \sqrt {a^2+b^2} d^2 e n} \\ \end{align*}
Result contains complex when optimal does not.
Time = 4.65 (sec) , antiderivative size = 1181, normalized size of antiderivative = 4.06 \[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\frac {(e x)^{2 n} \text {csch}\left (c+d x^n\right ) \left (1-\frac {2 b x^{-2 n} \left (-\frac {i \pi \text {arctanh}\left (\frac {-a+b \tanh \left (\frac {1}{2} \left (c+d x^n\right )\right )}{\sqrt {a^2+b^2}}\right )}{\sqrt {a^2+b^2}}-\frac {2 \left (c+i \arccos \left (-\frac {i b}{a}\right )\right ) \arctan \left (\frac {(a-i b) \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )+\left (-2 i c+\pi -2 i d x^n\right ) \text {arctanh}\left (\frac {(-i a+b) \tan \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )-\left (\arccos \left (-\frac {i b}{a}\right )-2 \arctan \left (\frac {(a-i b) \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )\right ) \log \left (\frac {(a+i b) \left (a-i b+\sqrt {-a^2-b^2}\right ) \left (1+i \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}{a \left (a+i b+i \sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}\right )-\left (\arccos \left (-\frac {i b}{a}\right )+2 \arctan \left (\frac {(a-i b) \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )\right ) \log \left (\frac {i (a+i b) \left (-a+i b+\sqrt {-a^2-b^2}\right ) \left (i+\cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}{a \left (a+i b+i \sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}\right )+\left (\arccos \left (-\frac {i b}{a}\right )+2 \arctan \left (\frac {(a-i b) \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )-2 i \text {arctanh}\left (\frac {(-i a+b) \tan \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )\right ) \log \left (-\frac {(-1)^{3/4} \sqrt {-a^2-b^2} e^{-\frac {c}{2}-\frac {d x^n}{2}}}{\sqrt {2} \sqrt {-i a} \sqrt {b+a \sinh \left (c+d x^n\right )}}\right )+\left (\arccos \left (-\frac {i b}{a}\right )-2 \arctan \left (\frac {(a-i b) \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )+2 i \text {arctanh}\left (\frac {(-i a+b) \tan \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )}{\sqrt {-a^2-b^2}}\right )\right ) \log \left (\frac {\sqrt [4]{-1} \sqrt {-a^2-b^2} e^{\frac {1}{2} \left (c+d x^n\right )}}{\sqrt {2} \sqrt {-i a} \sqrt {b+a \sinh \left (c+d x^n\right )}}\right )+i \left (\operatorname {PolyLog}\left (2,\frac {\left (i b+\sqrt {-a^2-b^2}\right ) \left (a+i b-i \sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}{a \left (a+i b+i \sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}\right )-\operatorname {PolyLog}\left (2,\frac {\left (b+i \sqrt {-a^2-b^2}\right ) \left (i a-b+\sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}{a \left (a+i b+i \sqrt {-a^2-b^2} \cot \left (\frac {1}{4} \left (2 i c+\pi +2 i d x^n\right )\right )\right )}\right )\right )}{\sqrt {-a^2-b^2}}\right )}{d^2}\right ) \left (b+a \sinh \left (c+d x^n\right )\right )}{2 a e n \left (a+b \text {csch}\left (c+d x^n\right )\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.88 (sec) , antiderivative size = 577, normalized size of antiderivative = 1.98
method | result | size |
risch | \(\frac {x \,{\mathrm e}^{\frac {\left (2 n -1\right ) \left (-i \operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right ) \pi +i \operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2} \pi +i \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2} \pi -i \operatorname {csgn}\left (i e x \right )^{3} \pi +2 \ln \left (e \right )+2 \ln \left (x \right )\right )}{2}}}{2 a n}-\frac {2 b \,{\mathrm e}^{-i \pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )} {\mathrm e}^{i \pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}} {\mathrm e}^{i \pi n \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}} {\mathrm e}^{-i \pi n \operatorname {csgn}\left (i e x \right )^{3}} {\mathrm e}^{\frac {i \operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right ) \pi }{2}} {\mathrm e}^{-\frac {i \operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2} \pi }{2}} {\mathrm e}^{-\frac {i \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2} \pi }{2}} {\mathrm e}^{\frac {i \operatorname {csgn}\left (i e x \right )^{3} \pi }{2}} e^{2 n} {\mathrm e}^{c} \left (\frac {x^{n} d \left (\ln \left (\frac {a \,{\mathrm e}^{2 c +d \,x^{n}}+{\mathrm e}^{c} b -\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}{{\mathrm e}^{c} b -\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}\right )-\ln \left (\frac {a \,{\mathrm e}^{2 c +d \,x^{n}}+{\mathrm e}^{c} b +\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}{{\mathrm e}^{c} b +\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}\right )\right )}{2 \sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}+\frac {\operatorname {dilog}\left (\frac {a \,{\mathrm e}^{2 c +d \,x^{n}}+{\mathrm e}^{c} b -\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}{{\mathrm e}^{c} b -\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}\right )-\operatorname {dilog}\left (\frac {a \,{\mathrm e}^{2 c +d \,x^{n}}+{\mathrm e}^{c} b +\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}{{\mathrm e}^{c} b +\sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}\right )}{2 \sqrt {a^{2} {\mathrm e}^{2 c}+{\mathrm e}^{2 c} b^{2}}}\right )}{a e n \,d^{2}}\) | \(577\) |
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Leaf count of result is larger than twice the leaf count of optimal. 1183 vs. \(2 (271) = 542\).
Time = 0.30 (sec) , antiderivative size = 1183, normalized size of antiderivative = 4.07 \[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\text {Too large to display} \]
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\[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\int \frac {\left (e x\right )^{2 n - 1}}{a + b \operatorname {csch}{\left (c + d x^{n} \right )}}\, dx \]
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\[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\int { \frac {\left (e x\right )^{2 \, n - 1}}{b \operatorname {csch}\left (d x^{n} + c\right ) + a} \,d x } \]
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\[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\int { \frac {\left (e x\right )^{2 \, n - 1}}{b \operatorname {csch}\left (d x^{n} + c\right ) + a} \,d x } \]
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Timed out. \[ \int \frac {(e x)^{-1+2 n}}{a+b \text {csch}\left (c+d x^n\right )} \, dx=\int \frac {{\left (e\,x\right )}^{2\,n-1}}{a+\frac {b}{\mathrm {sinh}\left (c+d\,x^n\right )}} \,d x \]
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